Engineering Physics Full Syllabus- Handwritten Notes

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Electromagnetics Numericals With Solutions

Electromagnetics (Numerical Problems) 1. If the earth receives 2 cal/min-cm2 solar energy from sun, calculate the amplitudes of …

A lamp radiates 500 W power uniformly in all directions. Calculate the electric and magnetic field intensities at 1 m distance from the lamp.

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If the magnitude of electric field vector in a plane wave is 377 V/m, determine the magnitude of magnetic field vector for a plane wave in free space.

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Assuming that all the energy from a 1000 W lamp is radiated uniformly, calculate the average value of the intensity of electric field of radiation at a distance of 2 m from the lamp.

If the earth receives 2 cal/min-cm2 solar energy from sun, calculate the amplitudes of electric and magnetic field of radiation?

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A silica glass optical fiber has a core refractive index of 1.5 and cladding refractive index of 1.450. Calculate the numerical aperture of the optical fiber.

Optical Fiber Questions With Solutions

Ans1. https://akhandduttaengineering.blogspot.com/2020/06/determine-numerical-aperture-of-step.html Ans2. https://akhandduttaengineeri…

The refractive index of core of step index fibre is 1.50 and the fractional change in refractive index is 4 %. Estimate: (i) refractive index of cladding, (ii) numerical aperture, (iii) acceptance angle in air and (iv) the critical angle at the core-cladding interface.

Calculate the refractive indices of core and cladding of an optical fibre with a numerical aperture of 0.33 and their fractional difference of refractive indices being 0.02.

The refractive indices of core and cladding materials of a step index fibre are 1.48 and 1.45, respectively. Calculate: (i) numerical aperture, (ii) acceptance angle, and (iii) the critical angle at the core-cladding interface and (iv) fractional refractive indices change.

The numerical aparture of an optical fibre is 0.39. If the difference in the refractive indices of the material of its core and the cladding is 0.05, calculate the refractive index of material of the core.

A step index fiber has core refractive index 1.466, cladding refractive index 1.46. If the operating wavelength of the rays is 0.85 μm, calculate the cutoff parameter or normalized frequency and the number of modes which the fiber will support. The diameter of core is 50 μm.

If the fractional difference between the core and cladding refractive indices of the optical fiber is 0.0135 and numerical aperture NA is 0.2425, calculate the refractive indices of core and cladding materials.

Calculate the numerical aperture, acceptance angle and the critical angle of the fiber from the following data : n1 = 1.50 and n2 = 1.45.

An optical fibre has fibre index 1.36 and relative difference in index D = 0.025. Find the numerical aperture and the acceptance angle.

Determine the numerical aperture of a step index fibre when the core refractive index n1 = 1.5 and the cladding refractive index n2 = 1.48. Find the maximum angle for entrance of light if the fibre is placed in air.

Questions Of Electromagnetics With Solutions

Answer 1.  https://akhandduttaengineering.blogspot.com/2020/05/derive-maxwells-electromagnetic-field.html Answer 2.  https://akhanddut…

Explain fundamental laws of electrostatics & magnetostatics and then write electromagnetic field equations and describe their physical significance.

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Write short note on the properties of dielectric.

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