A step index fiber has core refractive index 1.466, cladding refractive index 1.46. If the operating wavelength of the rays is 0.85 μm, calculate the cutoff parameter or normalized frequency and the number of modes which the fiber will support. The diameter of core is 50 μm.

$A step index fiber has core refractive index 1.466, cladding refractive index 1.46. If the operating wavelength of the rays is 0.85 μm, calculate the cutoff parameter or normalized frequency and the number of modes which the fiber will support. The diameter of core is 50 μm.$

About the Author

"Meet Mr. Akhand Dutta, the visionary Founder and Owner of CEWA (Civil Engineering With Akhand Dutta). Currently, The Placement Coordinator for Structural Engineering at the prestigious National Institute of Technology, Kurukshetra. With a lif…

Civil Engineering With Akhand Dutta

A step index fiber has core refractive index 1.466, cladding refractive index 1.46. If the operating wavelength of the rays is 0.85 μm, calculate the cutoff parameter or normalized frequency and the number of modes which the fiber will support. The diameter of core is 50 μm.

About the Author

Post a Comment

Q.Explain the formation of Newton's rings with a ray diagram and derive the expression for determination of wavelength of light using Newton's ring experiment.

A point P is 50 mm away from both the reference planes. Draw its all possible projections.

What is sustainable infrastructure, and why is it important for the future of cities and communities?

Find the probability with which an energy level 0.02 eV below the Fermi level will be occupied at room temperature of 300 K and at 1000 K.

The critical field for niobium is 1 × 105 A/m at 8 K and 2 × 105 A/m at 0 K. Calculate the transition temperature of the element.