A step index fiber has core refractive index 1.466, cladding refractive index 1.46. If the operating wavelength of the rays is 0.85 μm, calculate the cutoff parameter or normalized frequency and the number of modes which the fiber will support. The diameter of core is 50 μm.

$A step index fiber has core refractive index 1.466, cladding refractive index 1.46. If the operating wavelength of the rays is 0.85 μm, calculate the cutoff parameter or normalized frequency and the number of modes which the fiber will support. The diameter of core is 50 μm.$

About the Author

Mr Akhand Dutta is the Founder and Owner of Civil Engineering With Akhand Dutta (CEWA) and Akhand Dutta Writes. Currently, a civil engineering student at Bipin Tripathi Kumaon Institute of Technology, Dwarahat, Almora, Uttarakhand and has done his …

Civil Engineering With Akhand Dutta

A step index fiber has core refractive index 1.466, cladding refractive index 1.46. If the operating wavelength of the rays is 0.85 μm, calculate the cutoff parameter or normalized frequency and the number of modes which the fiber will support. The diameter of core is 50 μm.

About the Author

Post a Comment

Q.Explain the formation of Newton's rings with a ray diagram and derive the expression for determination of wavelength of light using Newton's ring experiment.

Calculate the energy difference between the ground state and first excited state in eV for an electron in one-dimensional rigid box of length 1 A°. Mass of the electron = 9.1×10−³¹ kg and h = 6.626×10−³⁴ J-S.

A point P is 50 mm away from both the reference planes. Draw its all possible projections.

Find the temperature at which there is 1.0 % probability that a state with energy 0.5 eV above Fermi energy will be occupied.