Strength of Materials (SOM) GATE Solved Practice Questions | Part 2
A bar 0.3 m long is 50 mm square in the section for 120 mm of its length, 25 mm diameter for 80 mm, and of 40 mm diameter for the remaining length. If
GATE/ESE/PSU Solved Practice Questions (SOM)- Part 2
Topic: Stress, Strain and Young's Modulus
A bar 0.3 m long is 50 mm square in the section for 120 mm of its length, 25 mm diameter for 80 mm, and of 40 mm diameter for the remaining length. If a tensile force of 100 KN is applied to the bar, calculate the maximum and minimum stresses produced in it, and the total elongation. Take E= 200 GN/m² and assume a uniform distribution of load over the cross-sections.
[Ans. 204 MN/m², 40 MN/m². 0.1453 mm]
A brass rod 20 mm diameter was subjected to a tensile load of 40 kN. The extension of the rod was found to be 254 divisions in the 200 mm extension meter. If each division is equal to 0.001 mm, find the elastic modulus of brass.
[Ans. 100.25 GN/m²]
Find the total extension of the bar, shown in Figure for an axial pull of 40 KN.
[Ans. 0.225 mm]
A brass bar having a cross-sectional area: of 1000 mm² is subjected to axial forces. as shown in Figure. Find the total change in length of the bar. Take E = 105 GN/m².
[Ans. 0.1143 m (decrease)]
A circular rod 0.2 m long, tapers from 20 mm diameter at one end to 10 mm diameter at the other. On applying an axial pull of 6 kN, it was found to extend by 0.068 mm. Find Young's modulus of the material of the rod.
[Ans. 112.3 GN/m²]
A vertical rod 3 m long is rigidly fixed at the upper end and carries an axial tensile load of 50 kN force. The rod tapers uniformly from a diameter of 50 mm at the top to 30 mm at the bottom. Calculate the total extension of the bar. Take density of material = 1 x 10^5 kg/m³ and E= 210 GN/m².
[Ans. 0.6217 mm]
Questions Courtesy - SOM by R. K. Rajput
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