For a circular curve of radius 200 m, the coefficient of lateral friction of 0.15 and the design speed is 40 kmph. The equilibrium superelevation (for equal pressure on the inner and outer wheel) would be

For a circular curve of radius 200 m, the coefficient of lateral friction of 0.15 and the design speed is 40 kmph. The equilibrium superelevation (for

For a circular curve of radius 200 m, the coefficient of lateral friction of 0.15 and the design speed is 40 kmph. The equilibrium superelevation (for equal pressure on the inner and outer wheel) would be

A. 21.3
B. 7
C. 6.3
D. 4.6

The correct answer is option C. 6.3. Can you explain this answer in the comments?

Book For Transportation Engineering MCQs and Solved Question - CLICK TO VIEW

For a circular curve of radius 200 m, the coefficient of lateral friction of 0.15 and the design speed is 40 kmph. The equilibrium superelevation (for equal pressure on the inner and outer wheel) would be

Getting Info...

About the Author

Mr. Ashutosh Nautiyal is a student who is pursuing his post-graduation (MBA in Infrastructure Development and Management) from SCMHRD, Pune. He has done his B.Tech in Civil Engineering from BTKIT, Dwarahat and his schooling from Omkarananda Saraswat…

Civil Engineering With Akhand Dutta

For a circular curve of radius 200 m, the coefficient of lateral friction of 0.15 and the design speed is 40 kmph. The equilibrium superelevation (for equal pressure on the inner and outer wheel) would be

For a circular curve of radius 200 m, the coefficient of lateral friction of 0.15 and the design speed is 40 kmph. The equilibrium superelevation (for equal pressure on the inner and outer wheel) would be

The correct answer is option C. 6.3. Can you explain this answer in the comments?

Book For Transportation Engineering MCQs and Solved Question - CLICK TO VIEW

About the Author

إرسال تعليق

Determine the transition temperature and critical field at 4.2 K for a given specimen of a superconductor if the critical fields are 1.41 × 105 and 4.205 × 105 A/m at 14.1 K and 12.9 K, respectively.

A point P is 50 mm away from both the reference planes. Draw its all possible projections.

Calculate the energy difference between the ground state and first excited state in eV for an electron in one-dimensional rigid box of length 1 A°. Mass of the electron = 9.1×10−³¹ kg and h = 6.626×10−³⁴ J-S.

Find the temperature at which there is 1.0 % probability that a state with energy 0.5 eV above Fermi energy will be occupied.

State the quadrants in which the following points lie. (i) P, its Top view is 40 above x-y; its FV 20 below the top view (ii) Q, both of its views coincide at a point 40 below x-y.